Line 21: | Line 21: | ||
1 x Used Peogeot front wheel bearing (spindle).<br> | 1 x Used Peogeot front wheel bearing (spindle).<br> | ||
- | 24 x Neodymium Magnets (2"x1"x0.5") | + | 24 x Neodymium Magnets (2"x1"x0.5")<br> |
- | 2 breakdisks (cheapest new one.) | + | 2 breakdisks (cheapest new one.)<br> |
- | 1 x 12mm threaded rod | + | 1 x 12mm threaded rod<br> |
- | 1.6 mm copper wire for coild (9 coild @ 77 windings) | + | 1.6 mm copper wire for coild (9 coild @ 77 windings)<br> |
- | Misc. wood/metal for making wood templates, metal supports. | + | Misc. wood/metal for making wood templates, metal supports.<br> |
- | + | Vinyl cast resin + Accelerator + Fiberglass Cloth.<br> | |
- | Vinyl cast resin + Accelerator + Fiberglass Cloth. | + | |
The number of coild have been done by pure testing, wind a coil, and place it in the one-coil-support shown above, and wind it at give RPM and check the output, and its a simple job of device/multiply to get the coild cound you need for the given RPM. My target is 160-180 RPM. | The number of coild have been done by pure testing, wind a coil, and place it in the one-coil-support shown above, and wind it at give RPM and check the output, and its a simple job of device/multiply to get the coild cound you need for the given RPM. My target is 160-180 RPM. | ||
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Calculations: | Calculations: | ||
- | As I want to wire the coils in "Y" configuration, the math is as follows: | + | As I want to wire the coils in "Y" configuration, the math is as follows:<br> |
- | Rectified DC output = phaseVoltage*1,73*1,414 | + | Rectified DC output = phaseVoltage*1,73*1,414<br> |
- | And as I need 3 coils pr phase, the PhaseVoltage have to be divided by 3, sp if I want 24 DV out on the DC Side of the rectifier, we want to be able to measure 3,27 VAC on one coil. | + | And as I need 3 coils pr phase, the PhaseVoltage have to be divided by 3, sp if I want 24 DV out on the DC Side of the rectifier, we want to be able to measure 3,27 VAC on one coil.<br> |
- | What energy is in the wind: | + | |
- | (m^2)*6*(m/s)^2 = Watt | + | What energy is in the wind:<br> |
- | With this, its possible to calculate the potential energy in the wind at what speed. | + | (m^2)*6*(m/s)^2 = Watt<br> |
+ | With this, its possible to calculate the potential energy in the wind at what speed.<br> |
Wind Generator building
In the times of green power making its way, I naturally also wants to try out some concepts of how I can generate green power for my own household - That may be in a form of electricity or heat.
So the concept is again to make something on hobby basis, that is cheap but will perform acceptable. The aim is to make a generator that is capable of making 1KW. The biggest challenge is that as im living in a normal houseing area, i dont expect I will be able to raise a high mill to be afficient, and I dont want it to be noisy, so from those requirements I dont expect the output will be 1KW - Therefore it will be interrestingf for me to see how much is actually possible to get out of the total setup.
After searching the web, I have found many different designs for home build alternators, and there seems to be a common approch that is efficient and cheap.
Unfortunately the project was worked on some time before I thought of documenting the progress, so thers not that manmy pictures of the early stages of the build process, but this is what I have:
The List of components are are the following:
1 x Used Peogeot front wheel bearing (spindle).
24 x Neodymium Magnets (2"x1"x0.5")
2 breakdisks (cheapest new one.)
1 x 12mm threaded rod
1.6 mm copper wire for coild (9 coild @ 77 windings)
Misc. wood/metal for making wood templates, metal supports.
Vinyl cast resin + Accelerator + Fiberglass Cloth.
The number of coild have been done by pure testing, wind a coil, and place it in the one-coil-support shown above, and wind it at give RPM and check the output, and its a simple job of device/multiply to get the coild cound you need for the given RPM. My target is 160-180 RPM.
Calculations:
As I want to wire the coils in "Y" configuration, the math is as follows:
Rectified DC output = phaseVoltage*1,73*1,414
And as I need 3 coils pr phase, the PhaseVoltage have to be divided by 3, sp if I want 24 DV out on the DC Side of the rectifier, we want to be able to measure 3,27 VAC on one coil.
What energy is in the wind:
(m^2)*6*(m/s)^2 = Watt
With this, its possible to calculate the potential energy in the wind at what speed.